13. The force F needed to keep the block at
equilibrium in given figure is (pulley and string are
detailed explanation plzz
Answers
Let the tension in the string be 'T' .
Since, net force along the string is 0.
=> F-T=0
=> F=T
2) Now,
Tension is constant along the string .
=> Tension on both sides of pulley is 'T'.
We need, to find the value of 'F' to keep the system in equilibrium .
=> Net force on pulley must be 0.
=> 2T-Mg = 0
=> T = mg/2.
Hence, the value of F=T=Mg/2.
hope that helps
Answer:
(3) Mg/2
Explanation:
1) Let the tension in the string be 'T' .
Since, net force along the string is 0.
=> F-T=0
=> F=T
2) Now,
Tension is constant along the string .
=> Tension on both sides of pulley is 'T'.
We need, to find the value of 'F' to keep the system in equilibrium .
=> Net force on pulley must be 0.
=> 2T-Mg = 0
=> T = mg/2.
Hence, the value of F=T=Mg/2.
hope it helps
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