Question

13. The H.C.F of (15, 12) = 18 - 3x then find the value of 'x'.
14. Find the zeros of the cubic polynomial x2 – x3.
PLEASE ANSWER THE QUESTION QUICKLY..........​

Answer 1

Answer:

5

Step-by-step explanation:

HCF(15,12) = 18-3x

3 = 18-3x

3+3x = 18

3x = 18-3

3x=15

X = 15/3

X = 5.

Answer 2

HCF(15,12)=18-3x____eq1

Q.13. So,HCF(15,12) =3

18-3x=3(from eq1)

3x=18-3

3x=15

x=15/3

x=5(ans).

Q.14. x^2-x^3=0

x^2(1-x)=0

1-x=0 And x^2=0

x=1 and x=0(ans)

☺HOPE IT IS HELPFUL. ☺