Question

13. The horizontal distance between two towers is 80 m. The angle of depression of the
top of the first tower when seen from the top of the second tower is 30. If the height
of the second tower is 160 m, find the height of the first tower.​

Answer 1

Answer:

From the figure, height of second tower = AC + CE

                                                         = AC + 160      (CE = 160)

Step-by-step explanation:

Now in Δ ABC,

tan 30° = AC/BC

=> 1/√3 = AC/80

=> AC* √3 = 80

=> AC = 80/√3

=> AC = (80*√3)/(√3*√3)

=> AC = (80*√3)/3

So height of first tower = AC+CE

= (80*√3)/3 + 160 m

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