Math, asked by shahinanjum457, 6 months ago

13. The length, breadth and height of an open-air swimming pool are 50 m, 30 m and 1.5
m. Find the cost of cementing its base and walls at the rate of +45 per square metre.​

Answers

Answered by Dev9911
1

Answer:

we know that curved surface area of a cuboid is 2h (l+b) and area of 1 side of a rectangle is b×l

so total cementing of swimming pool is 2h (l+b)+b×l

2×2.5 (50+30)+50×30

=>400+1500=1900sq/m

so costing is 27×1900=RS 51300

Step-by-step explanation:

Answered by Mehdihasanfarasta
0

Answer:

51300 I hope it help you and make me brainliest answers

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