13. The length, breadth and height of an open-air swimming pool are 50 m, 30 m and 1.5
m. Find the cost of cementing its base and walls at the rate of +45 per square metre.
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Answer:
we know that curved surface area of a cuboid is 2h (l+b) and area of 1 side of a rectangle is b×l
so total cementing of swimming pool is 2h (l+b)+b×l
2×2.5 (50+30)+50×30
=>400+1500=1900sq/m
so costing is 27×1900=RS 51300
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51300 I hope it help you and make me brainliest answers
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