Question

13) The % of Calicum in calcium carchonate i
aj 40
B). 30
c) 48
d) 36​

Answer 1

Answer:

40

Explanation:

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Answer 2

Answer:

40%

Explanation:

Molecular mass of CaCO3

= 40 + 12 + 3 × 16

= 100 amu

Mass of calcium in 1 mole of CaCO3 = 40 gm Percentage of calcium = 40100 × 100 = 40 %

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