Question

13. The Olympic high jump record is 2.45m held by Cuba let acceleration due to gravity
on earth was - 1m/s2 and not -10m/s2. Calculate the height to which the jumper
would have jumped?
any pls answer this class its emergency??​

Answer 1

Answer: 24.5m

Explanation:

Answer 2

Answer:

24.5 m

Explanation:

We are given that

Height  record=2.45 m

Acceleration due to gravity on earth=$-1 m/s^2$

We have to find the height to which the jumper would have jumped.

When the jumper reached at maximum height then final velocity=0

$v^2-u^2=2gS$

Substitute the values then we get

$0-u^2=2(-10)(2.45)$

$u^2=49$

$u=\sqrt{49}=7 m/s$

Initial velocity=7 m/s

g=$-1m/s^2$

Initial position of jumper at y=0

Therefore, $y-y_0=y-0=y$

Substitute the values in the above formula then we get

$0-49=2(-1)y$

$-49=-2y$

$y=\frac{49}{2}=24.5 m$

Hence, height to which jumper would have jumped=24.5 m