Math, asked by gokusharma008, 11 months ago

13.THE PERIMETERS OF TWO SIMILAR TRIANGLES TRIANGLE ABC AND TRIANGLE PQR ARE 35CM AND 49CM RESPECTIVELY.THE RATIO OF THE CORRESPONDING SIDES OF THE TRIANGLE IS______.​

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Answered by prince140691
2

Answer:

ratio of 35 and 49 is 5/7

so corresponding sides of the triangle are in the ratio 5/7

Step-by-step explanation:

ratio of perimeter of the triangle is equal to the ratio of corresponding sides

Answered by Anonymous
0

The areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.

Let first triangle altitude be x then second one's is x+10

so, Area of first triangle/area of second triangle=altitude of first triangle/altitude of second triangle

so, 49/64=(x/x+10)²

so, (7/8)²=(x/x+10)²

so, 7/8=x/x+10

so, 7(x+10)=8x

so, 7x+70=8x

so, 7x-8x=-70

so, x=70

So, first triangle's altitude is 70 cm

and the second one's is 80 cm

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