13. The polynomials (2x + x? - ax + 2) and (2x - 3x2 – 3x + a) when divided
by (x-2) leave the same remainder. Find the value of a.
13
(y
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Answer:
2x + x - ax + 2+2x - 3x2 – 3x + a
= −ax−3x2+a+2x+2
= −ax−3x2+a+2x+2/(x-2)+13y
= −ax2−3x3+3ax+8x2−2a−4x+2/x-2 + 13y
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