13. The polynomials (2x + x? - ax + 2) and (2x - 3x2 – 3x + a) when divided
by (x - 2) leave the same remainder. Find the value of a.
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Answer:
Firstly
2x+x²-ax+2=R
x-2=0
x=2
p(2)=2×2+2²-a2+2=R
=4+4-2a+2=R
=10-2a=R. (1)
secondly:
2x-3x²-3x+a=R
p(2)=2×2-3×2²-3×2+a=R
= 4-12-6+a=R
=a-14=R (2)
From (1) and (2)
10-2a=a-14
10+14=a+2a
24=3a
24/3=a
8= a
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