13. The probability of getting at least one head when we toss 3 unbiased coins is
Answers
Let's assume that H be for head and T for tail.
Total number of outcomes when three unbiased coins are tossed simultaneously:-
- HHH,
- HHT,
- HTH,
- HTT,
- THH,
- THT,
- TTH,
- TTT
In our given question, we need exact one head, which is appeared in 3 tosses: - HTT, THT and TTH. So these are the possible outcomes for exact one head.
When we tossed 3 coins, there were total 8 equally likely outcomes.
This is observed by taking the number of simultaneous outcomes(2), heads and tails, and then raising it to the power of the number of events(3), 2³ = 2×2×2 = 8
And therefore, probability for exact one head will be 3/8.
Explanation:-
Here, to calculate the probability of getting at least one head or tale, we can have to calculate the probability of getting 1 head, 2 heads and 3 heads and sum them up to get the required probability.
- ㅤㅤㅤㅤㅤ 3 unbiased coins are tossed
- Probability of getting one head when 3 coins are toosed simultaneously
When three unbiased coins are tossed , we get -
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ HHH
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ HHT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ HTH
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ HTT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ TTT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ TTH
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ THT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ❄ TTT
Now , we have to write the one heads when three coins are tossed.
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ⚡THT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ⚡ HTT
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ⚡TTH
By applying the formula:-