Question

13.
The ratio of the sum of n terms of two ap is (70+1): (4n+ 27). Find the ratio of their Mth terms..​

Answer 1

Answer:

Step-by-step explanation:

let a,A be the first terms and d,D be the common difference of two APs.

                    Sn1/Sn2=n/2[2a+(n-1)d]/n/2[2A+(n-1)D]

                                  =7n+1/4n+27

 2a+(n-1)d/2A+(n-1)D=7n+1/4n+27 

a+(n-1/2)d/A+(n-1/2)D=7n+1/4n+27

               putting,n-1/2=m-1

                                 n=2m-1

    a+(m-1)d/A+(m-1)D=7(2m-1)+1/4(2m-1)+27

                        am/Am=14m-6/8m+23 

 ratio=14m-6:8m+23

Hope it helps you....