Math, asked by viveksandbox, 10 months ago

13. The Simple Interest on Rs.5000 in 4 years @ y% p.a. equals the Simple Interest on Rs.8000 @ 10% p.a. in 2 years. Find the value of y.​

Answers

Answered by sohailpathan967
1

Answer:

valur of y is 8

Step-by-step explanation:

I =PRT/100

I=5000×X×4/100

I=200X

NEXT

I=8000×10×2/100

I=1600

HENCE

1600/200=8

Answered by Swarup1998
0

The value of y is 8.

Tips:

If I interest is obtained from an amount P for n years at the simple interest rate r% per year, then we have the relation,

I=\dfrac{Ptr}{100}

Step-by-step explanation:

Step 1.

The simple interest on Rs. 5000 in 4 years at y% p.a. is

I_{1}=\dfrac{5000\times 4\times y}{100}

\Rightarrow I_{1}=200y

Step 2.

The simple interest on Rs. 8000 in 2 years at 10% p.a. is

I_{2}=\dfrac{8000\times 2\times 10}{100}

\Rightarrow I_{2}=1600

Step 3.

According to the question, I_{1}=I_{2}

⇒ 200y = 1600

\Rightarrow y=\dfrac{1600}{200}

y = 8

Thus the value of y is 8.

#SPJ3

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