13. The sum of the digits of a number is 7. The difference between the number and the number
obtained by reversing its digits is 27. What is the number?
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Let the digit at tens place be x and the digit at ones place be y.
Then, number = 10x+y
According to question, x + y = 7
On reversing the digits, number becomes 10y + x
given that (10y + x)-(10x + y)= 27
9y - 9x = 27
y-x = 3
and y+x = 7
on adding both equations,
2y=10
y=5
x=2
Hence the number is 25 or 52
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