Math, asked by huitmamahuit, 2 months ago

13 The three vertices of a square ABCD are A (3,2). B (-2, 2) and D (3,-3). Find the coordinates of C and the area of square ABCD.​

Answers

Answered by ItzRoyalQueen01
94

Answer:

Thus, the coordinates of C are (-2,-3). Side of sq ABCD =CD=(2+3) units = 5 units. ∴ar(sqABCD)=(5×5)sq units = 25 sq units.

Answered by tilochna766013
2

Answer:

A- FIRST QUADRANT

B- SECOND QUADRANT

C- FOURTH QUADRANT

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