Math, asked by Pradeep7702, 7 months ago

13. The value of k for which the equation kx (x - 2) + 6 = 0 has non real roots is

Answers

Answered by dkchakrabarty01
0

Answer:

The eqn is kx^2 - 2kx + 6 = 0

Here a = k, b= -2k, c = 6

Roots will be unreal if determinant is less than zero

b^2 - 4ac is less than 0

(-2k)^ - 4(k)(6) is less than 0

4k^2 is less than 24k

k^2 less than 6k

k less than 6 Ans

Similar questions