Question

13.
The value of k such that line 2x+3y+4+k(6x-y+12) = 0 is
perpendicular to the line 7x + 5y = c is​

Answer 1

Answer:

Slope of line 7x+5y-4=0 is -5/7 Slope of given line is (k-3)/(2+6k) For perpendicular lines M1*M2=-1 =>(k-3)/(2+6k)*(-5/7)=-1 =>k=-29/37.

Step-by-step explanation:

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