Question

13. The value of p(t) = 2+t+2t2-t3 when t=0 is
(A) 2
(B) 1
(C) 4
(D) 0​

Answer 1

Answer:

2 + 0 + 2*0^2 - 0^3

2 + 0 + 0 - 0

2

Answer 2

Given,

p(t) = 2 + t + 2t² - t³.

To find,

The value of p(t) when t = 0.

Solution,

We can find the value of p(t) = 2 + t + 2t² - t³, by putting p(0).

p(t) = 2 + t + 2t² - t³.

Substituting the value of t as 0.

⇒   p(0) = 2 + (0) + 2(0)² - (0)³

⇒   p(0) = 2.

Hence, the value of p(t) = 2 + t + 2t² - t³ when t = 0 is 2. (OPTION A) .