Question

13.The value(s) of k for which 2x² -kx+k-0 has equal roots is/are_​

Answer 1

Step-by-step explanation:

∣x

2

+4x+3∣+2x+5=0

∣(x+1)(x+3)∣+2x+5=0

Now from the expression (x+1)(x+3), we can see that the expression is negative for values lying between −1 and −3.

So, for values not lying between −1 and −3 we can write equation as x

2

+6x+8=0

(x+2)(x+4)=0

x cannot be equal to −2 as x cannot lie between −1 and −3

∴x=−4

For values in the range of −3 to −1 we can write equation as

−x

2

−4x−3+2x+5=0

−x

2

−2x+2=0

x

2

+2x−2=0

x=

2

−2±

12

x=

3

−1 is discarded since it lies outside the −3 to −1

So, x=−1−(

3

) and −4