Question

13. Time period of a simple pendulum is measured to
be T = (0.8+- 0.01) s, then absolute error in the
measurement is
(1) 0.01 s
(2) 0.02 s
(3) 0.05 s
(4) 0.8 s​

Answer 1

Answer:

mean absolute error is 0.01 s

Answer 2

Answer:

Absolute error in the measurement is 0.01s i.e.option(1).

Explanation:

First, let's understand what is an absolute error.

"The magnitude of the difference between the real value of the quantity and the individual measurement value is called absolute error of the measurement".It is denoted by |Δx|. The mod value is always positive irrespective of the value of x. The absolute error is calculated as,

$x_a_b_s_o_l_u_t_e=|x_m_e_a_s_u_r_e_d-x_a_c_c_e_p_t_e_d|$    (1)

So, the time period in terms of errors is given as,

$T'=T\pm\Delta T$     (2)

T'=time period with errors

T=theoretical value of time period

ΔT=absolute error in measurement of the time period

From the question we have,

$T=0.8\pm0.01$      (3)

After comparing equation (3) with equation (2) we get;

$\Delta T=0.01s$      (4)

Hence, absolute error in the measurement is 0.01s i.e.option(1).