Question

13. Two bodies A and B of mass 1 kg
and 2 kg, respectively, are dropper
near the earth's surface. Let the
acceleration of A and B be al and a2
respectively, then
​

Answer 1

Answer:

Hey Mate..!

Step-by-step explanation:

I find the answer like this.!

$\huge\mathfrak\pink{Answer ©™}$

if the question has asked to find the time when they reach the bottom then it will be same for both A and B .

as we know H = 0t + 1/2 gt^2 or t = (2H/g)^2

● Only the impulse of heavier body will be more .

Their acceleratn has to be Same .

if Suppose they are a1 and a2 . Then it may be due to air friction and also air is different in the places where A and B are dropped.

● Therefore in that case consider net acceleration to be a1 and a2 .

a1 = g - (accln due to air friction in atmosphere1)

a2 = g - (accln due to air friction in atmosphere 2)

Answer 2

If the question has asked to find the time when they reach the bottom then it will be same for both A and B .

as we know H = 0t + 1/2 gt^2 or t = (2H/g)^2

● Only the impulse of heavier body will be more .

Their acceleratn has to be Same .

if Suppose they are a1 and a2 . Then it may be due to air friction and also air is different in the places where A and B are dropped.

● Therefore in that case consider net acceleration to be a1 and a2 .

a1 = g - (accln due to air friction in atmosphere1)

a2 = g - (accln due to air friction in atmosphere 2)

Mark ❤️