Question

13. Two cubes of masses 3 g and 6 g and sides of
length 2 cm and 3 cm respectively are placed on
a smooth table as shown in the figure. Calculate
the pressure experienced by the table due to the
system of boxes. [Take g = 10 m/s2]​

Answer 1

Answer:

14.2 Pascal

Step-by-step explanation:

Force (F1) of cube 1 = Mass*Acceleration = 3*10 = 30 N

Force (F2) of cube 2 = 6*10 = 60 N

Area (A1) of cube 1 = S*S = 2*2 = 4 cm^2

Area (A2) of cube 2 = S*S = 3*3 = 9 cm^2

Total pressure (P) = (F1/A1) + (F2/A2)

P = (30/4) + (60/9) = 7.5 + 6.7

P = 14.2 Pascal

Answer 2

Answer-

Total mass-3+6=9 grams=9/1000kg

Total weight=9/1000*10=9/100N

Area given=3cm=3/100m

Let area be l.

Area=l^2(l square)=9/100*100

P=F/A=1/1/100(by reducing)=100 Pa