Question

13. Two parallel wires P and Q placed at a separation of
6cm carry current 5A and 3A in opposite direction
respectively. Find the point on the line PQ where
resultant magnetic field is zero. What will happens if
current flows in same direction?​

Answer 1

Answer:

4 cm away from P

Explanation:

Two parallel wires P and Q placed at a separation of

6cm carry current 5A and 3A in opposite direction

respectively. Find the point on the line PQ where

resultant magnetic field is zero.

Let say at a distance of d  from Q  the magnetic field is zero

then distance from P = 6 + d

Magnetic filed ∝  Current / Distance

Mangnetic field by P   =  k  5/(6+d)  (k is Constant)

Magntic field by Q = k 3 /d  

k  5/(6+d)  =  k 3 /d

=> 5d = 18 + 3d

=> 2d = 18

=> d = 9

9 cm away from Q  & 15 cm away from P

if  current flows in same direction then Magnetic field will in between P & Q will be zero

Let say at a distance of d  from P  the magnetic field is zero

then distance from Q = 6 - d

Magnetic filed ∝  Current / Distance

Mangnetic field by P   =  k  5/d   (k is Constant)

Magntic field by Q = k 3 /(6-d)  

k  5/d  =  k 3 /(6-d)  

=> 6 (6-d) = 3d

=> 36 - 6d = 3d

=> 36 = 9d

=> d = 4

4 cm away from P towards Q

Answer 2

Answer:

Explanat4 cm away from P

Explanation:

Two parallel wires P and Q placed at a separation of

6cm carry current 5A and 3A in opposite direction

respectively. Find the point on the line PQ where

resultant magnetic field is zero.

Let say at a distance of d  from Q  the magnetic field is zero

then distance from P = 6 + d

Magnetic filed ∝  Current / Distance

Mangnetic field by P   =  k  5/(6+d)  (k is Constant)

Magntic field by Q = k 3 /d  

k  5/(6+d)  =  k 3 /d

=> 5d = 18 + 3d

=> 2d = 18

=> d = 9

9 cm away from Q  & 15 cm away from P

if  current flows in same direction then Magnetic field will in between P & Q will be zero

Let say at a distance of d  from P  the magnetic field is zero

then distance from Q = 6 - d

Magnetic filed ∝  Current / Distance

Mangnetic field by P   =  k  5/d   (k is Constant)

Magntic field by Q = k 3 /(6-d)  

k  5/d  =  k 3 /(6-d)  

=> 6 (6-d) = 3d

=> 36 - 6d = 3d

=> 36 = 9d

=> d = 4

4 cm away from P towards Qion: