Question

13.
Velocity time (v - t) graph for a particle is given in
the figure below. Distance travelled by particle in first 4s will be


Pls give ans with proper explanation ​

Answer 1

Answer:

area covered by velocity time graph=displacement

distance=16+8=24 metre

for distance we have to add because

distance=|displacement|

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Answer 2

${ \huge{ \textbf{Here,}}}$

.${ \boxed{ \large{u = 0 \: {ms}^{ - 1} }}} \\ { \boxed{ \large{v = 4 \: {ms}^{ - 1} }}} \\ { \boxed{ \large{t = 4 \: sec}}}$

Therefore,

${ \large{ \boxed{ \boxed{a = \frac{v - u}{t} }}}} = > \frac{4 - 0}{4} = \frac{4}{4} = { \red{1 \: {ms}^{ - 2} }}$

Now,

${ \large{ \boxed{ \boxed{s = ut + \frac{1}{2} {at}^{2} }}}} \\ \\ = > (0 \times 4) + \frac{1}{2} \times 1 \times {4}^{2} \\ \\ = > \frac{1}{2} \times 16 = { \red{8 \: m}}$