Question

13. Vishwas borrowed a total amount of Rs30,000 part of It on simple interest, rate of
419Cannot
12 p.c.p.a. and remaining on simple interest rate of 10 p.c.p.a. If at the end of 2
years he paid in all Rs36,480 to settle the loan amount, what was the amount bor
rowed at 12 p.c.p.a.?
(1) Rs 16000
(2) Rs18000
(3) Rs17500 (4) Rs 12000​

Answer 1

Let the sum borrowed at 12% p.a. be Rs. x

and that borrowed at 10% p.a. be Rs. (30000 - x)

S.I. at the end of 2 years

= Rs. (36480 - 30000)

= Rs. 6480

$\sf \green{( \dfrac{x \times 12 \times 2}{100}) + (\dfrac{ (30000−x) \times 10 \times 2}{100}) = 6480}$

$\pink⇔ \sf \blue{24x+600000−20x=648000} \\ \orange ⇔ \sf \red{4x=48000} \\ \green ⇔ \sf \purple{x=12000}$

Answer 2

Step-by-step explanation:

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