13. What is the smallest number to be added to 1000 to make the sum divisible by both 22 and 6?
Answers
bro answer is 56
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Given : divisible by both 22 and 6
To Find : . What is the smallest number to be added to 1000 to make the sum divisible by both 22 and 6
Solution:
A number divisible by both 22 and 6
must be divisible by LCM of 22 and 6
22 = 2 *11
6 = 2 * 3
LCM = 2 * 3 * 11 = 66
1000 + x divisible by 66
15
66 _| 1000
66
____
340
330
____
10
1000 = 66 * 15 + 10
1000 + x is divisible by 66
=> 66 * 15 + 10 + x
=> 10 + x must be divisible by 66
Hence x = 56
Hence 56 must be added o 1000 to make the sum divisible by both 22 and 6
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