13. What must be added to 2a3 + 5a - a2 - 6 to get a - a - a3 + 1 ?
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We get, the required result by subtracting
2a3 – a2 + 5a – 6 from –a3 + a2 – a + 1
=(-a3 + a2 – a + 1) – (2a3 – a2 + 5a – 6)
= - a3 + a2 – a + 1 – 2a3 + a2 – 5a + 6
= - a3 – 2a3 + a2 + a2 – a – 5a + 1 + 6
= -3a3 + 2a2 – 6a + 7
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Step-by-step explanation:
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