Question

13. What should be taken away from 3x2-4y2 + 5xy + 20 to obtain -x2- y2+6xy+20?​

Answer 1

Answer:

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Answer 2

Answer:

Let us assume (a) be the required term.

Then,

3x2 – 4y2 + 5xy + 20 – a = -x2 – y2 + 6xy + 20

a = 3x2 – 4y2 + 5xy + 20 – (-x2 – y2 + 6xy + 20)

a = 3x2 – 4y2 + 5xy + 20 + x2 + y2 – 6xy – 20

a = 3x2 + x2 – 4y2 + y2 + 5xy – 6xy + 20 – 20

a = 4x2 – 3y2 – xy