Question

13.When a 2 Ω resistor is connected across the terminals of a 6 V battery, the charge (in coulombs) passing through the resistor per second is:

0.5

2

3

4​

Answer 1

3

Explanation:

V = I R

6 = I * 2

I = 3 A

We know that Q = I t

for t = 1 sec

Q = 3 * 1 = 3 coloumb