Question

13). When ethyl bromide is
heated with alcoholic KOH---
- is formed.
o ethene
O ethane
O acetylene
O ethanol​

Answer 1

Explanation:

When ethyl bromide is heated with alcoholic potash (alc. KOH), ethylene is formed.

Answer 2

When Ethyl Bromide is heated with alcoholic KOH, Ethene is formed.

i.e., Option (1) is correct.

Explanation:

• When alkyl halides are reacted with a base such as KOH, two types of products may be formed.
• In the first case, when Alkyl halides are added to alkaline or aqueous KOH solution, then the formation of alcohol takes place i.e., here Substitution reaction takes place.
• Whereas when they are added to alcoholic KOH, major products formed are alkenes with the same number of carbons as in the alkyl halide, and alcohol is formed as a minor product i.e., in a very less proportion.
• In the above process, β - Elimination takes place and halogen acids are formed with alkenes.
• Now, in the above problem, when ethyl bromide is added to an alcoholic KOH solution, then Ethene would be formed along with KBr (Potassium Bromide) and H₂O (Water).

i.e.,                                            (heating)

C₂H₅-Br  +  Alcoholic KOH     --------------->     C₂H₄  +  K-Br  +  H₂O

Thus, Ethene is formed in the above reaction.

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