Question

13. Which term of A.P. 5, 15, 25, ......... will be
130 more than its 31st term ?​

Answer 1

In the given ap is first term is equal to 5 and common difference means d is equal to 10.

a=5,

c.d,d=10.

firstly we need to find the 31 term of this given a.p.

nth term =a +(n-1) d.

nth term = 5+30.10

nth term is equal to 305.

now 31st term is 305 and now we need and 130 according to the question.

305+130=435.

now we need to find that 435 is which term of the ap.

435=5+(n-1 )10.

430=(n-1)10.

430/10=n-1.

43=n-1.

[42=n] is the answer.

I think it may be help you.