(13) Write the hybridization and shape of [CoF6]3- and [Ni(CN)4]2-
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•The atomic number of Co is 27 and its valence shell electronic configuration is 3d74s2.
Co is in +3 oxidation state in the complex [CoF6]3-.
Hence, [CoF6]3- is sp3d2 hybridized and it is octahedral in shape.
•The atomic number of Ni is 28 and its valence shell electronic configuration is 3d84s2.
Ni is in +2 oxidation state in the complex [Ni(CN)4]2–.
Hence, [Ni(CN)4]2– is dsp2 hybridized and it is square planar in shape.
Hope it helped. ^___^
Co is in +3 oxidation state in the complex [CoF6]3-.
Hence, [CoF6]3- is sp3d2 hybridized and it is octahedral in shape.
•The atomic number of Ni is 28 and its valence shell electronic configuration is 3d84s2.
Ni is in +2 oxidation state in the complex [Ni(CN)4]2–.
Hence, [Ni(CN)4]2– is dsp2 hybridized and it is square planar in shape.
Hope it helped. ^___^
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0
Concept :The based on the hybridization of orbital which intermix to have stable orbital
Given :Write the hybridization and shape of [CoF6]3- and [Ni(CN)4]2-
Find : To find Hybridization
Solution : •The atomic number of Co is 27 and its valence shell electronic configuration is 3d74s2.
Co is in +3 oxidation state in the complex [CoF6]3-.
Hence, [CoF6]3- is sp3d2 hybridized and it is octahedral in shape.
•The atomic number of Ni is 28 and its valence shell electronic configuration is 3d84s2.
Ni is in +2 oxidation state in the complex [Ni(CN)4]2–.
Hence, [Ni(CN)4]2– is dsp2 hybridized and it is square planar in shape.
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