Question

13. Write the Pythagorean triplet whose one of the numbers is:
b. 4
a. 8
c. 12
d. 16​

Answer 1

(a) ans:- let 2m = 4

therefore:- m = 2

then, (m^2 - 1) and (m^2+1) are the Pythagorean triplet.

therefore m^2 - 1 = 4 -1 = 3

and m^2 +1 = 4 + 1 = 5

hence 3, 4 and 5 are in Pythagorean triplet.

(b) ans:- let 2m = 8

therefore m = 4

then, m^2 - 1 = 16 - 1 = 15

and, m^2 + 1 = 16 + 1 = 17

hence, 8, 15 and 17 are in Pythagorean triplet

(c) ans:- let 2m = 12

therefore m = 6

then, m^2 - 1 = 36 - 1 = 35

and, m^2 + 1 = 36 + 1 = 37

hence, 12, 35 and 37 are in Pythagorean triplet

(d) ans:- let 2m = 16

therefore m = 8

then, m^2 - 1 = 64 - 1 = 63

and, m^2 + 1 = 64 + 1 = 65

hence, 16, 63 and 65 are in Pythagorean triplet