Question

13- (x ² + 6x +11x-6) by (x35x t6)

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Answer 1

$\huge \fbox \purple{❥ Answer}$

x3−6x2+11x−6

=x3−5x2−x2+6x+5x−6

=x3−5x2+6x−x2+5x−6

=x(x2−5x+6)−1(x2−5x+6)

=(x−1)(x2−5x+6)

=(x−1)(x2−2x−3x+6)

=(x−1)[x(x−2)−3(x−2)]

=(x−1)(x−2)(x−3)

Answer 2

Answer:

x3−6x2+11x−6

=x3−5x2−x2+6x+5x−6

=x3−5x2+6x−x2+5x−6

=x(x2−5x+6)−1(x2−5x+6)

=(x−1)(x2−5x+6)

=(x−1)(x2−2x−3x+6)

=(x−1)[x(x−2)−3(x−2)]

=(x−1)(x−2)(x−3)