Question

13. (x + 2)(x - 1) = (x + 5)(x - 2)​

Answer 1

$\huge\red{\bold{\underline{\underline{Solution:-}}}}$

$(x + 2)(x - 1) = (x + 5)(x - 2) \\ \\ = > {x}^{2} - x + 2x - 2 = {x}^{2} - 2x + 5x - 10 \\ \\ = > {x }^{2} + x - 2 = {x}^{2} + 3x - 10 \\ \\ = > x - 2 = 3x - 10 \\ \\ = > 2x = 8 \\ \\ = > x = \frac{8}{2} = 4$

$\huge\green{\bold{\underline{\underline{Verification:-}}}}$

Substituting x value in the equation ,

$(4 + 2)(4 - 1) = (4 + 5)(4 - 2) \\ \\ = > (6)(3) = (9)(2) \\ \\ = > 18 = 18$

Since LHS = RHS ,

$\huge\fbox{\color{teal}{Hence\:\:\:verified}}$

Answer 2

X=4
Substituting value of x in the equation,
(6x3) = (9x2)
18=18
Thus LHS=RHS
hence proved....
Hope it helps