13(y-4)-3(y-9)-5(y+4)=0
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Answered by
9
Hey
Here is your answer,
13(y-4)-3(y-9)-5(y+4)=0
13y - 52 - 3y + 27 - 5y -20=0
13y -8y -25 -20=0
5y -45=0
5y = 45
y=45/5
y=9
Hope it helps you!
Here is your answer,
13(y-4)-3(y-9)-5(y+4)=0
13y - 52 - 3y + 27 - 5y -20=0
13y -8y -25 -20=0
5y -45=0
5y = 45
y=45/5
y=9
Hope it helps you!
nishthapoddar:
thanks
Answered by
1
13(y-4)-3(y-9)-5(y+4)=0
13y-52-3y+27-5y-20=0
13y-3y-5y-52-20+27=0
13y-8y-72+27=0
5y-45=0
5y=45
Y=9
I hope this will helpu
By DEVANSH
13y-52-3y+27-5y-20=0
13y-3y-5y-52-20+27=0
13y-8y-72+27=0
5y-45=0
5y=45
Y=9
I hope this will helpu
By DEVANSH
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