Math, asked by nishthapoddar, 1 year ago

13(y-4)-3(y-9)-5(y+4)=0

Answers

Answered by sijasubbiah
9
Hey

Here is your answer,

13(y-4)-3(y-9)-5(y+4)=0

13y - 52 - 3y + 27 - 5y -20=0

13y -8y -25 -20=0

5y -45=0

5y = 45

y=45/5

y=9

Hope it helps you!

nishthapoddar: thanks
nishthapoddar: okk
nishthapoddar: wlcm
Answered by devansh01
1
13(y-4)-3(y-9)-5(y+4)=0
13y-52-3y+27-5y-20=0
13y-3y-5y-52-20+27=0
13y-8y-72+27=0
5y-45=0
5y=45
Y=9





I hope this will helpu
By DEVANSH
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