Question

13(y-4) - 3 (y-9) - 5(y+4) = 0

Answer 1

$13y - 52 - 3y + 27 - 5y - 20 = 0 \\ 5y - 45 = 0 \\ 5y = 45 \\ y = 9$

Answer 2

your answer is...

13(y-4)-3(y-9)-5(y+4)=0
13y-52-3y+27-5y-20=0
13y-8y-52+7=0
5y-45=0
5y=45
y=9

Hope it will help u...
✌️✌️✌️✌️