Math, asked by pawankumargarsanda08, 11 months ago

13. यदि 6432 और 123 के महत्तम समापवर्तक में 3 घटा दें तो शेष निम्नलिखित में कौन-
(i) 0 (ii) 1
(ii) 3
(iv) 4​

Answers

Answered by rajivrtp
1

Answer:

(1). 0

Step-by-step explanation:

6432= 3× .......not needed to another factor

and not divisible by 41

123= 3× 41

HCF= 3 ( only one common prime factor exist)

then ans = 3-3=0

answer = (1) 0

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