13 (z-4)-3 (z-9)-5 (z+4)=0
Answers
Answered by
19
Hey friend...!!!
13( z - 4) - 3(z - 9) - 5( z + 4) = 0
13z - 52 - 3z + 27 - 5z - 20 = 0
5z - 45 = 0
5z = 0 + 45
5z = 45
Z = 45/5
Z = 9
Hope it helps...!!!
13( z - 4) - 3(z - 9) - 5( z + 4) = 0
13z - 52 - 3z + 27 - 5z - 20 = 0
5z - 45 = 0
5z = 0 + 45
5z = 45
Z = 45/5
Z = 9
Hope it helps...!!!
astha1234:
Thank you for helping.
Similar questions