Question

(1300+1200)/?=208.33

Answer 1

Answer:12.0001

Step-by-step explanation:

let the no. be x

then 2500/x=208.33

on transposing,

2500/208.33=x

250000/20833=x

x=12.0001(approx.)

Answer 2

We are given an equation, where we have to find the value of "?".

Let's term the "?" as "x".

So our equation will look like;

$\dfrac{(1300+1200)}{\text{x}}=208.33$

So, now let's start solving it.

First let's Add up the numerator;

$\dfrac{(2500)}{\text{x}}=208.33$

Now, let's multiply x on both sides' i.e., L.H.S. and R.H.S.

$\dfrac{2500}{\cancel{\text{x}}}\times\cancel{\text{x}}=208.33\times\text{x}$

Now, as we have to isolate "x", we have to divide both sides by 208.33;

$\dfrac{2500}{208.33} = \dfrac{\cancel{208.33}\text{x}}{\cancel{208.33}}\\\\\implies \dfrac{2500}{208.33}=\text{x}$

Now to find the value of x we'll have to simplify the above equation;

x = 12.0002 (approx.)

Therefore, the value of "?" is 12.0002 (approx.)