Question

1300 ml aqueous find the solution of H_{2}*S * O_{4} is 30 % w/v mass of H_{2}*S * O_{4} in this solution.​

Answer 1

There is 30gm of urea present in aqueous solution in 100ml sol.

Therefore, height of this sol.=vol. of the sol.× density of sol.

=100×1.2=120g

Now mass of the solvent (Water) =120−30=90g