131) A particle is projected from a horizontal plane with a
velocity of 8 V2 ms- at an angle 8. A highest point
its velocity is found to be 8 ms 1. Its range will be
(g = 10 ms )
a) 3.2 m
b) 4.6 m
c) 6.4 m
d) 12.8 m
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Answer:
d) 12.8m
Explanation:
Give v=8m/s ; u=theta(√2)
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