Math, asked by 1970kumart, 10 months ago

132
Example 3 : A wooden toy rocket is in the
shape of a cone mounted on a cylinder, as
shown in Fig. 15.8. The height of the entire
rocket is 26 cm, while the height of the conical ,
part is 6 cm. The base of the conical portion
has a diameter of 5 cm, while the base
diameter of the cylindrical portion is 3 cm. If
the conical portion is to be painted orange
and the cylindrical portion yellow, find the
area of the rocket painted with each of these
colours. (Take n = 3.14)​

Answers

Answered by harshraut2004
1

Answer:

where is the figure

Step-by-step explanation:

give the pic of the figure

Answered by rishit2290
1

Answer:

Answer:

➖➖➖➖➖

Orange colour = 51.05 sq-cm

Yellow color= 188.49 sq-cm

Solution:

➖➖➖➖

Curved surface area of cone = π r l

Here r (radius) = 2.5 cm

Since radius is half of Diameter.

l = slant height

from right angle triangle as mentioned in the diagram ,l is hypotenuse,it can be calculated by Pythagoras theorem.

A.T.Q conical part is to painted orange ,So orange colour is required to paint CURVED SURFACE AREA of cone

=

The part if the rocket to be painted yellow,is the CSA of cylindrical shape = 2πrh

here h (height) = 20 cm

Radius (r) = 1.5 cm

Orange paint to be painted on 51.05 sq-cm area,

Yellow paint to be painted on 188.49 sq-cm area.

Hope it helps you.

Thanks for asking such a nice question.

Read more on Brainly.in - https://brainly.in/question/5484414#readmore

Similar questions