Question

13²=x²+(x-7)². step by step
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Answer 1

Answer:

Step-by-step explanation:

Start by expanding (x-7)^2. You get

x^2+x^2-14x+49=13^2

Transpose 13^2

0=2x^2-14x+49-169

=2x^2-14x-120

2 is a common factor, so you can divide the entire polynomial with 2,

2x^2/2-14x/2-120/2

We will get

x^2-7x-60

Now, using the factorization method, we have to find the common factors for -60 (keep in mind of the sign)

Common factors of -60: -12 and 5 (12 is negative because both 7 and 60 have the Negative sign)

Then,

x^2-12x+5x-60

x(x-12)+5(x-12)

(x+5)(x-12)

Now we have to find the zeros, there will be two

x+5=0

x=-5

x-12=0

x=12

Therefore, the two zeros are -5 and 12

Answer 2

In an right triangle APB

x²+ (x-7)² = (13)²