Question

132x
2
−251x+117=0thenfindthepossiblevauleofx​

Answer 1

How to solve your problem

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132x^{2}-251x+117

132x2−251x+117

Grouping

1

Use the sum-product pattern

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132x^{2}{\color{#c92786}{-251x}}+117

132x2−251x+117

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0

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132x^{2}{\color{#c92786}{-108x}}{\color{#c92786}{-143x}}+117

132x2−108x−143x+117

2

Common factor from the two pairs

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132x^{2}-108x-143x+117

132x2−108x−143x+117

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2

(

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1

−

9

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−

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3

(

1

1

−

9

)

12x(11x-9)-13(11x-9)

12x(11x−9)−13(11x−9)

3

Rewrite in factored form

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12x(11x-9)-13(11x-9)

12x(11x−9)−13(11x−9)

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(12x-13)(11x-9)

(12x−13)(11x−9)

Solution

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