Math, asked by bansalanushka042, 2 months ago

1331×121×0.11=(1.1)? ×11000

Answers

Answered by probrainsme102
0

Answer:

1.4641

Step-by-step explanation:

Multiply the value of the RHS then divides by the multiplication of RHS then the outcome will replace the question mark in the equation.

Given: 1331×121×0.11=(1.1)? ×11000

To find: Value of ?

Calculation:

Equation:1331×121×0.11=(1.1)? ×11000

LHS: 1331×121×0.11

1331×121×0.11=17,715.61

RHS: (1.1)x? ×11000

Let ? is z then

(1.1)xz ×11000=12100z

Den dived the value

1331×121×0.11=(1.1)? ×11000

17,715.61=12100z

z=17,715.61/12100

z=1.4641

Put the value of z in the RHS side value.

(1.1)xz ×11000=(1.1)x1.4641 ×11000

=17,715.61

So, the final equation is

1331×121×0.11=(1.1)x1.4641  ×11000

17,715.61=17,715.61

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Answered by smithasijotsl
0

Answer:

The value of x = 5

Step-by-step explanation:

Given,

1331×121×0.11=(1.1)? ×11000

To find,

The value of the unknown

Recall the concept

xᵃ × xᵇ =xᵃ⁺ᵇ

\frac{x^a}{x^b} = x^{a-b}

Solution:

Let the unknown value be 'x', Then the expression becomes

1331×121×0.11=(1.1)ˣ ×11000 ---------------(1)

We have, 1331 = 11³

121 = 11²

0.11 = \frac{11}{100}

11000 = 11 ×1000

Substituting these values in equation (1) we get

11³×11²× \frac{11}{100} = (1.1)ˣ ×11×1000

11³×11²×11 = (1.1)ˣ ×11×1000 ×100

Applying the identity xᵃ × xᵇ =xᵃ⁺ᵇ we get

11⁶ = (1.1)ˣ ×11×10³ ×10²

11⁶ = (1.1)ˣ ×11×10⁵

\frac{11^6}{11X10^5} = (1.1)^x

applying \frac{x^a}{x^b} = x^{a-b} we get

\frac{11^5}{10^5}  = (1.1)^x

(1.1)⁵ = (1.1)ˣ

Comparing both sides we get

x = 5

The value of x = 5

#SPJ2

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