1331xcubey- 11y cube x
Answers
Answer:
11×11×11=1331
Step-by-step explanation:
so the cube root of 11 is 1331
Step-by-step explanation:
1331=we divide 1331 into groups of three digits starting from the right. So 1331 has two groups one is 331 and another is 1.
For first group 331, the digit 1 is at one's place .1 comes at a unit place of a number only when its cube root ends with 1. So one's place of the required cube root is 1.
For another group, i.e.1
and
so 1 lies between 0 and 8.the smaller number among 1 and 2 are 1. So the one's place of 1 is 1 and ten's place of cube root 1331 is 1
Hence
For 4913
we divide 4913 into groups of three-digit starting from the right. So 4913 has two groups one is 913 and another is 4.
For first group 913, the digit 3 is at one's place .3 comes at a unit place of a number only when its cube root ends in 7. So one's place of the required cube root is 7.
For another group, i.e.1 and so 4 lies between 1 and 8.the smaller number among 1 and 2 are 1. So the one's place of 1 is 1 and ten's place of cube root 4913 is 1
Hence
For 12167
we divide 12167 into groups of three-digit starting from the right. So 12167 has two groups one is 167 and another is 12.For first group 167, the digit 7 is at one's place .7 comes at a unit place of a number only when its cube root ends in 3. So one's place of the required cube root is 3
For another group, i.e.12 and so 12 lies between 8 and 27.the smaller number among 2 and 3 are 2. So the one's place of 2 is 2itself and ten's place of cube root 12167 is 2
Hence
For 32768
we divide 32768 into groups of three-digit starting from the right. So 32768 has two groups one is 768 and another is 32.
For first group 768, the digit 8 is at one's place .8 comes at the unit place of a number only when its cube root ends in 2. So one's place of the required cube root is 2.For another group, i.e.1 and so 32 lies between 27 and 64.the smaller number among 3 and 4 are 4.So the ten's place of cube root 32768 is 3
Hence
3√32768=32