Question

134. One year ago, a man was 8 times
as old as his son. Now his age is
equal to the square of his son's age.
Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

let age of son one yr ago be x

age of man one yr ago be 8x

.....

age of son after one year = x+1

age of man after one year = 8x+1

....

now accordind to question..

8x+1= (x+1)^2

8x+1=x^2 + 1 +2x

after solving

8x = x^2 +2x

now...x^2 - 6x=0

solving this we get ...x=0 and x = 6 but

age cant be zero...so..x=6...

age of son is x+1 = 7 years

and age of man be 8x+1= 49...ans..