Question

136/-119 standard form is​

Answer 1

By fraction rule

$\sf{{\dfrac{a}{-b}} = -{\dfrac{a}{b}} = - {\dfrac{136}{119}}}$

Factor the number 136 = 17 × 8

$\sf {=-{\dfrac{17×8}{119}}}$

Factor the number 119 = 17 × 7

$\sf{=-{\dfrac{17×8}{17×7}}}$

Cancel the common factor 17

$\sf{=-{\dfrac{\bcancel{17}×8}{{\bcancel{17}}×7}}} \\\\ \sf{=-{\dfrac{8}{7}}}$

Answer 2

SOLUTION

TO DETERMINE

The standard form of

$\displaystyle\sf{ \frac{136}{ - 119} }$

EVALUATION

Here the given number is

$\displaystyle\sf{ \frac{136}{ - 119} }$

$\displaystyle\sf{ = - \frac{136}{ 119} }$

Now

Numerator = 136 = 2 × 2 × 2 × 17

Denominator = 119 = 7 × 17

So the common factor between numerator and denominator is 17

Dividing both of the numerator and denominator by 17 we get

$\displaystyle\sf{ \frac{136}{ - 119} }$

$\displaystyle\sf{ = - \frac{136}{ 119} }$

$\displaystyle\sf{ = - \frac{8}{ 7} }$

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