1365 by which no. divisible toe get 31 quotient and 32 remainder
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hi
aim : 1365 by which no. divisible toe get 31 quotient and 32 remainder
let the number be x
dividiened = 1365
qoutient = 31
remainder = 32
so lets form an euqation
1365 = (31 *x) + 32
1365 = 31x + 31
1365 - 32 = 31x
1333 = 31x
x = 1333/31
x = 43
hence 43 is the no. divisible toe get 31 quotient and 32 remainder
hope it helps u
:)
aim : 1365 by which no. divisible toe get 31 quotient and 32 remainder
let the number be x
dividiened = 1365
qoutient = 31
remainder = 32
so lets form an euqation
1365 = (31 *x) + 32
1365 = 31x + 31
1365 - 32 = 31x
1333 = 31x
x = 1333/31
x = 43
hence 43 is the no. divisible toe get 31 quotient and 32 remainder
hope it helps u
:)
Raghav3333:
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