137 men participate in a knock-out singles tennis tournament. If the total number of players in a particular round is odd then one person gets a bye to the next round. What is the minimum number of matches required to decide the winner?
Answers
Given : 137 men participate in a knock-out singles tennis tournament. If the total number of players in a particular round is odd then one person gets a bye to the next round.
To Find : the minimum number of matches required to decide the winner
Solution:
137 men for 1st round
1st round Matches = (137 - 1)/2 = 68 and 1 bye
Hence Men for 2nd round = 68 + 1 = 69
2nd round Matches = (69- 1)/2 = 34 and 1 bye
Hence Men for 3rd round = 34 + 1 = 35
3rd round Matches = (35- 1)/2 = 17 and 1 bye
Hence Men for 4th round = 17 + 1 = 18
4th round Matches = (18)/2 = 9
Hence Men for 5th round = 9
5th round Matches = (9-1)/2 = 4 and 1 bye
Hence Men for 6th round = 4 + 1 = 5
6th round Matches = (5-1)/2 = 2 and 1 bye
Hence Men for 7th round = 2 + 1 = 3
7th round Matches = (3-1)/2 = 1 and 1 bye
Hence Men for 8th round = 1 + 1 = 2
8th round Matches = 2/2 = 1
Total Matches = 68 + 34 + 17 + 9 + 4 + 2 + 1 + 1
= 136 Matches
Another simple method :
There are 137 participants and one is winner
Hence 136 has to loose their matches
Hence there will be 136 matches
Learn More:
Team A wins 26 matches out of 52 matches. Team B wins three ...
brainly.in/question/11758874
7. If the number of teams are 15 1 pointthen , what would be ...
https://brainly.in/question/23231145